I did this before:
(1/5)[(x+2)/(x-3)]^6
perhaps you like this form:
(x+2)^6
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5(x-3)^6
4(x+2)^8 (x-3)^6
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20(x+2)^2 (x-3)^12
note:sorry that the expression on top of the line is so farr
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