Asked by alan
2/27(x-3)√((x^2-6x+23)/y)rearrange the equation to make y the subject
Answers
Answered by
MathMate
This expression has been the subject of a recent differential equation problem.
dy/dx=(2/27)(x-3)√((x^2-6x+23)/y)
in which case we can rearrange as
(√y)dy/dx=(2/27)(x-3)√(x^2-6x+23)
The given expression above is not an equation, so we do not know exactly what the expression equals (dy/dx, 0, 1...?)
dy/dx=(2/27)(x-3)√((x^2-6x+23)/y)
in which case we can rearrange as
(√y)dy/dx=(2/27)(x-3)√(x^2-6x+23)
The given expression above is not an equation, so we do not know exactly what the expression equals (dy/dx, 0, 1...?)
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