by prime factorisation method find the least positive number divisible by 700 and 364

Answer 1

First you have to prime factorize both numbers. The greatest common divisor(GCD) has the
lower number of prime factors that appear in both lists.

2 appears twice and 7 appears once on both lists 5,7 and 13 appear on one list only, so they and not "common" factors and do not appear in the GCD

364 = 91*4 = 2^2 * 7 * 13
700 = 2^2 * 5^2 * 7

GCD = 2^2 * 7 = 28

Answer 2

700 = 7x2x2x5x5
364 = 2x2x91

HCM = 7x2x2x5x5x91 = 63700

Answer 3

I assumed 91 was prime, ...

700 = 7x2x2x5x5
364 = 2x2x7x13

LCM = 7x2x2x2x2x13 = 9100

Answer 4

I read the problem incorrectly

Answer 5

Not satisfying