Asked by Gustavo
How do I go about finding the roots (real and complex) of this polynomial:
2x^3 + 7x^2 + 14x + 12
2x^3 + 7x^2 + 14x + 12
Answers
Answered by
Reiny
try x = ±1,±2,±3 ...
f(1) ≠0
f(-1) ≠0
...
I could not find any zeros with integer values of x,
so I tried some possible fractions and found
x = -3/2 to work
so it factors to (2x+3)((x^2 + 2x + 4) after a long division
so x = -3/2 or x = -1 ± i√3
f(1) ≠0
f(-1) ≠0
...
I could not find any zeros with integer values of x,
so I tried some possible fractions and found
x = -3/2 to work
so it factors to (2x+3)((x^2 + 2x + 4) after a long division
so x = -3/2 or x = -1 ± i√3
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