Asked by sarah
the only part i cant figure out is the max static friction force that acts on the block. please help show me how to find it
Suppose a block with mass 2.00 kg is resting on a ramp. If the coefficient of static friction between the block and the ramp is 0.320, what maximum angle can the ramp make with the horizontal before the block starts to slip down?
Use the values from PRACTICE IT to help you work this exercise. The ramp in the figure is roughed up and the experiment repeated.
(a) What is the new coefficient of static friction if the maximum angle turns out to be 29.6°?
its 0.567
(b) Find the maximum static friction force that acts on the block.
Suppose a block with mass 2.00 kg is resting on a ramp. If the coefficient of static friction between the block and the ramp is 0.320, what maximum angle can the ramp make with the horizontal before the block starts to slip down?
Use the values from PRACTICE IT to help you work this exercise. The ramp in the figure is roughed up and the experiment repeated.
(a) What is the new coefficient of static friction if the maximum angle turns out to be 29.6°?
its 0.567
(b) Find the maximum static friction force that acts on the block.
Answers
Answered by
bobpursley
force down ramp=force friction up rame
mgSinTheta=mu*mgCosTheta
tanTheta=mu
a) mu=tan29.6
b) max friction force=mu*mg*cosTheta
mgSinTheta=mu*mgCosTheta
tanTheta=mu
a) mu=tan29.6
b) max friction force=mu*mg*cosTheta
Answered by
sarah
this equation isnt giving me the right answer :/
Answered by
Paul
Find the fg y component because that is equal to the "n" in the equation:
F(static friction) = mu x n
F(static friction) = mu x n
Answered by
Anonymous
Snowmen and sledding are