Asked by JOY
How do you find the lateral area and surface area of a right prism whose height is 10 ft and whose base is a rombus with diagonals 12 ft and
12sq root of 3 ( DON'T KNOW HOW TO PUT SQROOT 3 IN)
12sq root of 3 ( DON'T KNOW HOW TO PUT SQROOT 3 IN)
Answers
Answered by
drwls
The area of a rhombus is 1/2 the product of the diagonals.
The top and bottom of your prism are rhombuses with areas of 60 sqrt3 ft^2, EACH.
The four rectangular sides of the prism each have areas of
(height)*[(a/2)^2 + (b/2)^2]
where a and b are the rhombus diagonal lengths. The term in brackets is the rhombus side length, and equals 12 feet in this case.
The top and bottom of your prism are rhombuses with areas of 60 sqrt3 ft^2, EACH.
The four rectangular sides of the prism each have areas of
(height)*[(a/2)^2 + (b/2)^2]
where a and b are the rhombus diagonal lengths. The term in brackets is the rhombus side length, and equals 12 feet in this case.
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