Question
Please can someone assist. What is the equation of the line that passes through the point (-2,3) and is perpendicular to the line 10x+2y=3. Thank you.
Answers
bobpursley
find the slope of your given line.
y=-5x+3/2 slope -5
the perpendicular is the negative reciprocal of -5 slope.
y= 1/5 x + b
now put the point in...
3=1/5(-2)+b and solve for b.
Now the equation is
y=mx +b and you have m, and b.
y=-5x+3/2 slope -5
the perpendicular is the negative reciprocal of -5 slope.
y= 1/5 x + b
now put the point in...
3=1/5(-2)+b and solve for b.
Now the equation is
y=mx +b and you have m, and b.