Asked by Joe

find the area of a parallelogram with diagonals of lengths 10 inches and 22 inches that intersect at a 65 degrees angle.
Answered by Reiny
We would have 4 equal triangles
let's look at one of these that contain the 65° angle.
Height/11 = sin65
height = 9.969

area = 4( (1/2)(5)(9.969) = 99.694
Answered by Joe
that last answer posted is wrong