Asked by Ron
c squared-4c-12=0
we have to solve each equation by completing the square.
we have to solve each equation by completing the square.
Answers
Answered by
Reiny
c^2 - 4c = 12
c^2 - 4 <b>+ 4</b> = 12 <b>+ 4</b>
(c-2)^2 = 16
c-2 = ±4
c = 6 or c = -2
c^2 - 4 <b>+ 4</b> = 12 <b>+ 4</b>
(c-2)^2 = 16
c-2 = ±4
c = 6 or c = -2
Answered by
Alyssa
when you added 4 on your second step, your 'c' dissapeared... where'd it go?
Answered by
Reiny
typo error, it should be there as 4c
If you expand (x-2)^2 you will see I did not lose it.
If you expand (x-2)^2 you will see I did not lose it.
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