Asked by esora

please help me solve this partial-fraction decomposition!

12x-57/(x-3)(x-10)

Answered by Reiny
let
A/(x-3) + B(x-10) = (12x-57)/((x-3)(x-10))

then
A(x-10) + B(x-3)/((x-3)(x-10)) = (12x-57)/((x-3)(x-10) )

or
A(x-10) + B(x-3) = 12x - 57
let x = 10
B(7) = 63 ----> B = 9

let x = 3
A(-7) = -21 ----> A = 3

so:
(12x-57)/((x-10)(x-3)) = 3/(x-3) + 9/(x-10)
Answered by Anonymous
thank you! :)
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