Asked by jann
How many grams of CaCl2 (molar mass = 111.0 g/mol) are needed to prepare 4.44 L of 0.500 M CaCl2 solution?
Answers
Answered by
DrBob222
How many moles do you need? M x L = moles.
Then moles CaCl2 = grams CaCl2/molar mass CaCl2.
Then moles CaCl2 = grams CaCl2/molar mass CaCl2.
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