Asked by Fate
A 30kg box of vegetable moves down a 35 degree frictionless inclined. Find the resultant force down the inclined and the acceleration down the inclined
Answers
Answered by
drwls
"inclined" is a past tense verb. You probably mean the noun "incline".
The weight force is W = M*g.
The force component down the incline is W sin 35 = M*g*sin35.
Divide that by M for the acceleration
The weight force is W = M*g.
The force component down the incline is W sin 35 = M*g*sin35.
Divide that by M for the acceleration
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