Question

For this equation
2 Ag+ (aq) + Cu(s) <--> Cu2+ (aq) + 2 Ag(s)

Which occurs at the anode?

A. Cu --> Cu2+ + 2e–
B. Cu2+ + 2e– --> Cu
C. Ag+ + e– -->Ag
D. Ag --> Ag+ + e–


A, right because it's oxidation?

Answer 1

Oxidation occurs at the anode. Which is losing electrons.

Answer 2

So Cu--> Cu2+ +2e- is losing electrons, right? Because its becoming positive

Answer 3

That's right and the equation of Cu ==> Cu^2+ + 2e shows it losing two electrons.