Asked by Jodi-
Please help-What is the equation of the ellipse with foci (0,6), (0,-6) and co-vertices (2,0),(-2,0)
My answer and logic is below but it can't be correct
I thought the answer would be x^2/4 + y^2/40 = 1 but that can't be because the choices are:
x^2/1 + y^2/40 = 1 or x^2/1 + y^2/36
I'm really confused because I think b^2=4, c^2=36 and a^2 = 40
My answer and logic is below but it can't be correct
I thought the answer would be x^2/4 + y^2/40 = 1 but that can't be because the choices are:
x^2/1 + y^2/40 = 1 or x^2/1 + y^2/36
I'm really confused because I think b^2=4, c^2=36 and a^2 = 40
Answers
Answered by
drwls
c^2 = 36
b^2 = 4
a^2 - b^2 = c^2, so
a^2 = b^2 + c^2 = 40
OK so far.
The major axis is the horizontal x = 0 line and the equation is
x^2/40 + y^2/4 = 1
I agree with your answer.
b^2 = 4
a^2 - b^2 = c^2, so
a^2 = b^2 + c^2 = 40
OK so far.
The major axis is the horizontal x = 0 line and the equation is
x^2/40 + y^2/4 = 1
I agree with your answer.
Answered by
Jodi-
Thank you-there must just be a mistake on the homework sheet for the selection of answers
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