Asked by Rachal
How can I find the exact value of Sin 480 degrees? Thanks
Answers
Answered by
Anonymous
480°=360°+120°
sin(480°)=sin(120°)
sin(90°+x)=sin(90°-x)
sin(90°+30°)=sin(90°-30°)
sin(120°)=sin(60°)
sin(480°)=sin(120°)=sin(60°)=sqroot(3)/2
sin(480°)=sin(120°)
sin(90°+x)=sin(90°-x)
sin(90°+30°)=sin(90°-30°)
sin(120°)=sin(60°)
sin(480°)=sin(120°)=sin(60°)=sqroot(3)/2
Answered by
Rachal
Thank you I see where I got stuck
Answered by
Parikshit
Sin(480) = sin (5x90 + 30) = cos 30 = sqrooy(3)/2
Answered by
shobhit
3/2
Answered by
Janani
Sin(360+120)
Sin 120
Sin (90+30)
+cos 30
3/2
Sin 120
Sin (90+30)
+cos 30
3/2
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