Asked by Marie

Identifying Conics. Put equation in standard form and graph.
9x^2-4y^2-90x+189=0
Answered by Mgraph
9(x^2-10x+25-25)-4y^2+189=0
9(x-5)^2-225-4y^2+189=0
9(x-5)^2-4y^2=36
(x-5)^2/2^2 - y^2/3^2=1 hyperbola