Asked by olek
give the solution of the initial-value problem
dx/dy=(1+2cos^2(x))/y, (y > 0), y= 1 when x = 0.
Thanks.
dx/dy=(1+2cos^2(x))/y, (y > 0), y= 1 when x = 0.
Thanks.
Answers
Answered by
Mgraph
dx/dy or dy/dx ?
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