Asked by Anonymous
how many moles of ca are needed to neutralize 8.87moles of H3po4
Answers
Answered by
bobpursley
write the balanced reaction:
3Ca+2H3PO4 >> 3H2 + Ca3(PO4)2
looks like 3/2 * 8.87 moles of Ca
3Ca+2H3PO4 >> 3H2 + Ca3(PO4)2
looks like 3/2 * 8.87 moles of Ca
Answered by
DrBob222
Write the equation and balance it. Using the coefficients in the balanced equation, convert moles Ca to moles H3PO4.