Asked by Anonymous
                how many moles of ca are needed to neutralize 8.87moles of H3po4
            
            
        Answers
                    Answered by
            bobpursley
            
    write the balanced reaction:
3Ca+2H3PO4 >> 3H2 + Ca3(PO4)2
looks like 3/2 * 8.87 moles of Ca
    
3Ca+2H3PO4 >> 3H2 + Ca3(PO4)2
looks like 3/2 * 8.87 moles of Ca
                    Answered by
            DrBob222
            
    Write the equation and balance it. Using the coefficients in the balanced equation, convert moles Ca to moles H3PO4. 
    
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