Asked by sophie
Apply logarithms to create a linear relationship:
((x^3)(y^1.5))/(z^.5)=k
((x^3)(y^1.5))/(z^.5)=k
Answers
Answered by
bobpursley
take the log of both sides:
3logx+1.5logy-.5logz=logk
3logx+1.5logy-.5logz=logk
Answered by
Anonymous
3*log(x)+1.5log(y)-0.5log(z)=log(k)
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