Asked by sophie

Apply logarithms to create a linear relationship:

((x^3)(y^1.5))/(z^.5)=k

14 years ago

Answered by bobpursley

take the log of both sides:

3logx+1.5logy-.5logz=logk

14 years ago

Answered by Anonymous

3*log(x)+1.5log(y)-0.5log(z)=log(k)

14 years ago

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