Asked by DestinyLashea
Find the surface area of the closed rectangular box shown
6cm, 5cm, 3cm
S.A.= (LW)+2(HL)+2(HW)
I did: (5x6)+2(5x3)+2(6x3)=96 am I correct?
6cm, 5cm, 3cm
S.A.= (LW)+2(HL)+2(HW)
I did: (5x6)+2(5x3)+2(6x3)=96 am I correct?
Answers
Answered by
MathMate
6cm, 5cm, 3cm
This formula for the surface area is for an <i>open</i> box with length L and width W:
S.A.(open)= (LW)+2(HL)+2(HW)
For a closed box, it would be:
S.A.(closed)= 2(LW+HL+HW)
You would do: <b>2</b>(5x6)+2(5x3)+2(6x3)=?
This formula for the surface area is for an <i>open</i> box with length L and width W:
S.A.(open)= (LW)+2(HL)+2(HW)
For a closed box, it would be:
S.A.(closed)= 2(LW+HL+HW)
You would do: <b>2</b>(5x6)+2(5x3)+2(6x3)=?
Answered by
DestinyLashea
126. thanks
Answered by
MathMate
You're welcome!
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