1+2+3+4+5+6+7+8 = 36
or, use the formula
n(n+1)/2 = $ 36 (n = 8)
or, use the formula
n(n+1)/2 = $ 36 (n = 8)
On Chris's first birthday, he receives $1.
On his second birthday, he receives $3, which is the previous year's amount ($1) multiplied by 3.
On his third birthday, he receives $6, which is the previous year's amount ($3) multiplied by 2.
On his fourth birthday, he receives $10, which is the previous year's amount ($6) plus 4.
Notice that the amount of money Chris receives each year is related to the previous year's amount.
Now, let's continue the pattern for the upcoming years:
On his fifth birthday, Chris will receive $10 (the previous year's amount) plus 5, which equals $15.
On his sixth birthday, Chris will receive $15 (the previous year's amount) multiplied by 2, which equals $30.
On his seventh birthday, Chris will receive $30 (the previous year's amount) multiplied by 2, which equals $60.
Finally, on his eighth birthday, Chris will receive $60 (the previous year's amount) plus 8, which equals $68.
Therefore, Chris will receive $68 on his eighth birthday if the pattern continues.