HELP ME PLEASE.
2x = 10
Use the Substitution method to solve the system of equations.
x + y = -4
x - y = 2
PLz HELP!!
I'M NOT BOB BUT I CAN HELP
ITS REALLY SIMPLE ALGEBRA
X + Y = -4......EQN 1
X - Y = 2.....EQN 2
From EQN 2, let
x = 2 + y
Substitute that into EQN 1
x - y = -4
(2+y) + y= -4
2 + 2y= -4
2y = -4-2
y = -6/2
y = -3
SUBST y= -3 in EQN 2
x -(-3) = 2
x + 3 = 2
x = 2-3
x= -1
Therefore
y = -3 and x = -1
x + y = -4
(2+y) + y= -4
2 + 2y= -4
2y = -4-2
y = -6/2
y = -3
Thanks,what abou this one?
Use the Substitution method to solve the system of equations.
x + y = 10
y = x + 8
Thanks,what abou this one?
Use the Substitution method to solve the system of equations.
x + y = 10
y = x + 8
just use the ones she helped you with before.
minus y on each side of one equation (IE x+y=10 is now x=10-y.
then fill in the 10-y for x in the second equation.
May be 2
help
x+y=10
y=x+8
I think it goes like this
x+x+8=10
2x+8=10
2x=10-8
2x=2 divide both sides by 2
x=1
1+y=10
y=10-1
y=9
x+y=10 replaced 1+9=10
y=x+8 replaced 9=1+8
was this a real problem to solve, or are you just testing me?
x+y=10
y=x+8
I think it goes like this
x+x+8=10
2x+8=10
2x=10-8
2x=2 divide both sides by 2
x=1
1+y=10
y=10-1
y=9
x+y=10 replaced 1+9=10
y=x+8 replaced 9=1+8
was this a real problem to solve, or are you just testing me?
x+y=10
y=x+8
I think it goes like this
x+x+8=10 (y is replaced by x+8)
2x+8=10 (add the x's to get 2x)
2x=10-8 (move 8 to the other side)
2x=2 divide both sides by 2
x=1
1+y=10
y=10-1
y=9
x+y=10 replaced 1+9=10
y=x+8 replaced 9=1+8
was this a real problem to solve, or are you just testing me?
x + 2 = -4 x - (-4) = 2
x + 2 - 2 = -4 - 2 x - (-4) + 4 = 2 + 4
x = 6 x = 6
checked: checked:
(-6) + 2 = -4 (6) - (-4) = 2
-4 = -4 2 = 2
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