Asked by Maria
A flywheel rotates with an angular speed of 26 rev/s. As it is brought to rest with a constant acceleration, it turns 55 rev.
What is the magnitude of the angular acceleration?
How much time does it take to stop?
What is the magnitude of the angular acceleration?
How much time does it take to stop?
Answers
Answered by
Henry
t = 55rev * (1/26)s/rev 2.1s.
a = (Vf - Vo) / t = (0 - 26) / 2.1 =
-12.4m/s^2.
a = (Vf - Vo) / t = (0 - 26) / 2.1 =
-12.4m/s^2.
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