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Question

express the trig. ratios sinA,secA n
tanA in terms of cotA.
14 years ago

Answers

tan A = 1/cotA

1/cotA^2 = sin^2A/cos^2A
= (1 - cos^2A)/cos^2A
= [1/cos^2A] - 1

1 + (1/cot^2A) = 1/cos^2A

sec^2A = 1 + (1/cot^2A)

The sign of secA will depend upon the quadrant A is in
14 years ago

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