Your course materials should have included the equation for the period:
T = 2 pi * sqrt(L/g)
In your case, L = 0.30 m and you must know what g is.
Perform the calculation of T, in seconds. Then use
f = 1/T , for the frequency in Hz
What is the period of this pendulum?
T = s
What is the frequency of this pendulum?
f = Hz
T = 2 pi * sqrt(L/g)
In your case, L = 0.30 m and you must know what g is.
Perform the calculation of T, in seconds. Then use
f = 1/T , for the frequency in Hz
Period (T) = 2Ļā(L/g)
Frequency (f) = 1/T
where:
L is the length of the pendulum
g is the acceleration due to gravity (approximately 9.8 m/s^2)
Given that the length of the pendulum is 0.30 m, and assuming the acceleration due to gravity is 9.8 m/s^2, we can substitute these values into the formulas.
Calculating the period (T):
T = 2Ļā(L/g)
T = 2Ļā(0.30/9.8)
T ā 2Ļā(0.0306122449)
T ā 2Ļ(0.1749072262)
T ā 1.0986 seconds
Therefore, the period of the pendulum is approximately 1.0986 seconds.
Calculating the frequency (f):
f = 1/T
f = 1/1.0986
f ā 0.9091 Hz
Therefore, the frequency of the pendulum is approximately 0.9091 Hz.
The period (T) of a simple pendulum can be calculated using the formula:
T = 2Ļ ā(L/g)
where:
T = period (in seconds)
L = length of the pendulum (in meters)
g = acceleration due to gravity (approximately 9.8 m/sĀ²)
In this case, the length of the simple pendulum is given as 0.30 m.
Now, let's substitute the given values into the formula:
T = 2Ļ ā(0.30/9.8)
T = 2Ļ ā(0.0306)
T ā 2Ļ * 0.1748
T ā 1.096 seconds
So, the period of this pendulum is approximately 1.096 seconds.
To find the frequency (f) of the pendulum, you can use the equation:
f = 1/T
where:
f = frequency (in Hertz)
T = period (in seconds)
Let's substitute the value we found for T into this equation:
f = 1/1.096
f ā 0.911 Hz
Therefore, the frequency of this pendulum is approximately 0.911 Hz.