The simple pendulum in a tall clock is 0.30 m long.

Your course materials should have included the equation for the period:

T = 2 pi * sqrt(L/g)

In your case, L = 0.30 m and you must know what g is.

Perform the calculation of T, in seconds. Then use

f = 1/T , for the frequency in Hz

Thank you DRWLS!

To calculate the period and frequency of a simple pendulum, we can use the following formulas:

Period (T) = 2π√(L/g)

Frequency (f) = 1/T

where:
L is the length of the pendulum
g is the acceleration due to gravity (approximately 9.8 m/s^2)

Given that the length of the pendulum is 0.30 m, and assuming the acceleration due to gravity is 9.8 m/s^2, we can substitute these values into the formulas.

Calculating the period (T):
T = 2π√(L/g)
T = 2π√(0.30/9.8)
T ≈ 2π√(0.0306122449)
T ≈ 2π(0.1749072262)
T ≈ 1.0986 seconds

Therefore, the period of the pendulum is approximately 1.0986 seconds.

Calculating the frequency (f):
f = 1/T
f = 1/1.0986
f ≈ 0.9091 Hz

Therefore, the frequency of the pendulum is approximately 0.9091 Hz.

To find the period of a simple pendulum, you need to know the length of the pendulum.

The period (T) of a simple pendulum can be calculated using the formula:

T = 2π √(L/g)

where:
T = period (in seconds)
L = length of the pendulum (in meters)
g = acceleration due to gravity (approximately 9.8 m/s²)

In this case, the length of the simple pendulum is given as 0.30 m.

Now, let's substitute the given values into the formula:

T = 2π √(0.30/9.8)

T = 2π √(0.0306)

T ≈ 2π * 0.1748

T ≈ 1.096 seconds

So, the period of this pendulum is approximately 1.096 seconds.

To find the frequency (f) of the pendulum, you can use the equation:

f = 1/T

where:
f = frequency (in Hertz)
T = period (in seconds)

Let's substitute the value we found for T into this equation:

f = 1/1.096

f ≈ 0.911 Hz

Therefore, the frequency of this pendulum is approximately 0.911 Hz.