Do you mean sqrt(x+1) or sqrt x + 1?
If the former, the indefinite integral is [(x+1)^3/2]/(3/2)
Evaluate it at x = 9 and x = 0 and take the difference.
Area = (2/3)*[(10)^(3/2) - 1]
Find the are under the given curve
y=square root of x + 1
from x=0 to x=9
Please walk me through each step.
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