perimeter = 36
so length + width = 18
so what length and width sum would get you 18 ?
l w Area
1 17 17
2 16 32
3 15 45
4 14 56
5 13 65
.....
9 9 81
notice that largest area is obtained when you create a square of 9 ft by 9 ft.
If you have 36ft of fencing, what are the areas of the different rectangles you could enclose with the fencing? Consider only whole-number dimensions.
This problem confused me. Any help??
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