Question

1. A certain playground merry-go-round is essentially an 90-kg iron disk 2.0 m in radius. Two children, each with a mass of 46 kg, are originally standing on opposite sides of the disk near its outer edge. The merry-go-round is turning essentially without friction about a vertical axis once every 5 s. The children then clamber toward each other so that they are only 1.2 m from the center. What is its angular velocity now? (You do not need to specify its direction.)

Answer 1

Hint: Angular momentum is conserved.

The initial angular velocity is
w1 = (2*pi)/5 = 1.26 rad/s

Moment of inertia of the platform is

I = (1/2) M R^2 = 180 kg*m^2

There is additional angular momentum due to the children. Conservation of angular momentum requires that:

I*w1 + 2 m*5*2^2*w1 = I*w2 + 2*m*1^2*w2

m is each child's mass. Solve for w2

Answer 2

jacky

Answer 3

yo momma's a ho