Question
Lets say we have a sample of 100 bacteria in a lab that doubles every 30 minutes. What formula would we apply here and how many bacteria would you expect to find in 35 minutes?
Answers
Damon
n = 100 e^(kt)
200 = 100 e^(30 k)
e^(30k) = 2
30 k = ln 2
k = .0231
so
n = 100 e^(.0231 t)
if t = 35
n(35min) = 100 e^(.0231*35)
= 224
200 = 100 e^(30 k)
e^(30k) = 2
30 k = ln 2
k = .0231
so
n = 100 e^(.0231 t)
if t = 35
n(35min) = 100 e^(.0231*35)
= 224