I guess your college/school is using an automated response system like the Open Universitiy's iCMA system based on the response. It is difficult to guess what is missing as the formatting is different. My guess would be
2OH^-(aq)--> O_2(g)+2H^+(aq)+4e^-(aq)
Complete and balance the following half-reactions. In each case indicate whether the half-reaction is an oxidation or reduction. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)
OH ‾(aq) �¨ O2(g)
I got 2OH^-(aq)-->O_2(g)+2H^+(aq)+4e^-
and its oxidation, but for some reason its wrong.
hint:Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript formatting.
..
3 answers
I did it correctly though right? I'm trying to figure out what's wrong with the format or maybe i solve the problem wrong. So far, the previous problems, the e^- has no state and they accepted it. I have no idea what's wrong haha.
Yes, your answer balances in terms of charge and atoms.
another (unlikely) possible answer is
2OH^-(aq)--> O_2(g)+H_2(g)+2e^-(aq)
My first choice would have been..
4OH^-(aq)--> O_2(g)+2H2O(l)+4e^-(aq)
another (unlikely) possible answer is
2OH^-(aq)--> O_2(g)+H_2(g)+2e^-(aq)
My first choice would have been..
4OH^-(aq)--> O_2(g)+2H2O(l)+4e^-(aq)
2 answers