Question

2Al+3H2SO4--> Al2(SO4)3+3H2
a.)determine the oxidation number of each element in both the reaction and products of this oxidation-reduction reaction of aluminum and sulfuric acid.
b.) what element is oxidized in this reaction?
c.) what element reduces in the reaction?

Answers

a.) Oxidation number of Al in the reactants: +3; Oxidation number of Al in the products: +3; Oxidation number of H in the reactants: +1; Oxidation number of H in the products: +1; Oxidation number of S in the reactants: +6; Oxidation number of S in the products: +6.
b.) Aluminum is oxidized in this reaction.
c.) Hydrogen is reduced in the reaction.

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