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Given the quadratic function f(x) = 16x2 – 64x + 64, find a value of x such that f(x) = 16.Asked by kozy
Given the quadratic function f(x) = 16x^2 – 64x + 64, find a value of x such that f(x) = 16.
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Answered by
Jay
16 = 16x^2 - 64x + 64
0 = 16x^2 - 64x + 64 - 16
(using quadratic formula)
x= 3 or x =1
0 = 16x^2 - 64x + 64 - 16
(using quadratic formula)
x= 3 or x =1
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