Asked by Kat
Use standard heats of formation in Appendix L to calculate standard enthalpy changes for the following reactions.
1.45 x 10-2 mol of carbon is oxidized to CO2(g)
Please help me!
1.45 x 10-2 mol of carbon is oxidized to CO2(g)
Please help me!
Answers
Answered by
DrBob222
Look up the heat of formation for CO2 in the table provided to you. My table has something like 393.5 kJ/mol. That reaction is for
C + O2 ==> CO2
delta H reaction is (n*deltaHf products) - (n*deltaHf reactants) =
(n*deltaHf CO2) - [(n*deltaHf C) + (n*deltaHf O2)]
delta Hrxn = -393.5 -(+0) = -393.5 kJ/mol.
You have 1.45E-2 mol instead of 1 mole; therefore, delta H rxn = -393.5 kJ/mol x 1.45E-2 mol = ?? kJ.
C + O2 ==> CO2
delta H reaction is (n*deltaHf products) - (n*deltaHf reactants) =
(n*deltaHf CO2) - [(n*deltaHf C) + (n*deltaHf O2)]
delta Hrxn = -393.5 -(+0) = -393.5 kJ/mol.
You have 1.45E-2 mol instead of 1 mole; therefore, delta H rxn = -393.5 kJ/mol x 1.45E-2 mol = ?? kJ.
Answered by
Kat
Thank you! but does n in (n*deltaHf products) - (n*deltaHf reactants) mean amount? What amount is it talkinging about?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.