Asked by Kenya
How do you find the inverse of functions? for example how would you find the inverse of y= log8 x
Answers
Answered by
MathMate
Let's try this for f(x)= y = e^(6x)
Step 1:
interchange x and y to get
x=e^(6y)
Step 2:
solve for y in terms of x:
ln(x) = ln(e^(6y)) = 6y
y = ln(x)/6
So
f<sup>-1</sup>(x) = ln(x)/6
Step 3:
Verify that f(f<sup>-1</sup>(x))=x (if the inverse was correct).
f(f<sup>-1</sup>(x))
=f(ln(x)/6)
=e^(6*ln(x)/6)
=e^(ln(x))
=x
So the inverse is correct.
Step 1:
interchange x and y to get
x=e^(6y)
Step 2:
solve for y in terms of x:
ln(x) = ln(e^(6y)) = 6y
y = ln(x)/6
So
f<sup>-1</sup>(x) = ln(x)/6
Step 3:
Verify that f(f<sup>-1</sup>(x))=x (if the inverse was correct).
f(f<sup>-1</sup>(x))
=f(ln(x)/6)
=e^(6*ln(x)/6)
=e^(ln(x))
=x
So the inverse is correct.
Answered by
Kenya
Ok that's slightly confusing.
I understand the flipping of x and y but then what do you do?
so x=log8 y
?
I understand the flipping of x and y but then what do you do?
so x=log8 y
?
Answered by
MathMate
Yes, then you solve for y in terms of x.
use the law of exponents:
e<sup>log(x)</sup>=x
or
8<sup>log8 y</sup>=y, etc.
(assuming log8 y is log(y) to the base 8)
raise both sides to power of 8 to get
8<sup>x</sup> = 8<sup>log8(y)<?sup>
Simplify and solve y in terms of x.
use the law of exponents:
e<sup>log(x)</sup>=x
or
8<sup>log8 y</sup>=y, etc.
(assuming log8 y is log(y) to the base 8)
raise both sides to power of 8 to get
8<sup>x</sup> = 8<sup>log8(y)<?sup>
Simplify and solve y in terms of x.
Answered by
MathMate
8<sup>x</sup> = 8<sup>log8(y)</sup> = y
Simplify and solve y in terms of x.
Simplify and solve y in terms of x.
Answered by
Webber
MMMMmmmmmmk that helps, thanks!
Answered by
MathMate
You're welcome!