Asked by jonah
Calculate the pH at each stage in the titration of 25.0 ml 0.10 M KOH(aq)
with 0.25 M HCl(aq).
1. Initiall ( before titration).
2. After addition of 5 ml of HCl.
3. After addition of 9.5 ml of HCl.
4. At the equivalent point.
5. After addition of 12 ml of HCl
with 0.25 M HCl(aq).
1. Initiall ( before titration).
2. After addition of 5 ml of HCl.
3. After addition of 9.5 ml of HCl.
4. At the equivalent point.
5. After addition of 12 ml of HCl
Answers
Answered by
Anonymous
1. Initial pH: 14 - pOH = 14- [-log(0.10 M KOH)]
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