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Original Question
Find the coordinates of the vertex of the graph of f(x)=2x^2+10-1Question
Find the coordinates of the vertex of the graph of f(x)=2x^2+10x-17.
Answers
bobpursley
find the zeroes:
2x^2+10x-17=0
x= (-10+-sqrt(100+136))/4
x= (-2.5+-3.84)
x= -6.34; 1.34
so halfway between those is the vertex,or at -2.5
2x^2+10x-17=0
x= (-10+-sqrt(100+136))/4
x= (-2.5+-3.84)
x= -6.34; 1.34
so halfway between those is the vertex,or at -2.5