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Asked by Lisa

A mixture of KCI and KClO3 weighing 1.80g was heated. The dry O2 generated occupied 140ml at STP. What percent of the original mixture was KCl03?
14 years ago

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Answered by DrBob222
You know 1 mol oxygen (32.0 grams) occupies 22.4L at STP. Convert 140 mL to grams, then,
%oxygen = (mass oxygen/mass original sample)*100 = ??%
14 years ago
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