Asked by Lisa
A mixture of KCI and KClO3 weighing 1.80g was heated. The dry O2 generated occupied 140ml at STP. What percent of the original mixture was KCl03?
Answers
Answered by
DrBob222
You know 1 mol oxygen (32.0 grams) occupies 22.4L at STP. Convert 140 mL to grams, then,
%oxygen = (mass oxygen/mass original sample)*100 = ??%
%oxygen = (mass oxygen/mass original sample)*100 = ??%
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.