Which set of side lengths shows similar triangles? (1 points)

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similar triangles will have the same proportion ratio for each of the similar sides. For instance, on A) is

40/10=20/5=50/8 ? If so, then it is similar.

I know the answer but you should try it yourself... you are acting way too desperate, this problem is not that hard, listen to what bobpursley said and think it out yourself instead of being lazy and asking around on the internet. :)

-HERP DERP!

dude are you cheating on a test

The vertices of triangle ABC are A(-2,2),B(6,2), and C(0,8). The perimeter of triangle ABC is

un el apo ches situalo si esco no en al mone como pista

To determine which set of side lengths shows similar triangles, we need to compare the ratios of the corresponding sides of the two triangles. If the ratios are the same, then the triangles are similar.

Let's compare the ratios of the corresponding sides for each option:

A) Triangle ABC: 40:20:50 = 2:1:2.5
Triangle XYZ: 10:4:8 = 2.5:1:2
The ratios of the sides are not the same, so these triangles are not similar.

B) Triangle ABC: 30:20:60 = 0.5:0.33:1
Triangle XYZ: 40:60:90 = 0.44:0.67:1
The ratios of the sides are not the same, so these triangles are not similar.

C) Triangle ABC: 110:80:60 = 1.37:1:0.55
Triangle XYZ: 6:8:5.5 = 1.09:1.45:1
The ratios of the sides are not the same, so these triangles are not similar.

D) Triangle ABC: 32:20:32 = 1.6:1:1.6
Triangle XYZ: 30:16:16 = 1.88:1:1
The ratios of the sides are the same, so these triangles are similar.

Therefore, the set of side lengths that shows similar triangles is option D) Triangle ABC: 32, 20, 32; Triangle XYZ: 30, 16, 16.