Question

law of cosines

m<c=60, a=12,b=15 triangle

Answer 1

The law of cosines is:

a^2 = b^2 + c^2 - 2cosA
or
b^2 = a^2 + c^2 - 2cosB
or
c^2 = a^2 + b^2 - 2cosC

the lower case letters are sides, the capital letters are for angles. For this problem, you would do

c^2 = 12^2 + 15^2 - 2cos60

That gives you side c. After that, you should be able to use the law of sines to find the other two angles of the triangle.