Asked by UnKnown
The active element of a certain laser is made of a glass rod 30cm long and 1.5cm in diameter. The average coefficient of linear expansion of glass is 9 x 10^-6°C-1. If the temperature of the rod increases by 65°C, what is the increase in its volume?
Answers
Answered by
bobpursley
Ok, most important is the change in length in a laser, but volume will be
coeffVolumeExpansion=appx 3*coeffLinearExpansion.
See the section isotropic materials:
http://en.wikipedia.org/wiki/Thermal_expansion
coeffVolumeExpansion=appx 3*coeffLinearExpansion.
See the section isotropic materials:
http://en.wikipedia.org/wiki/Thermal_expansion
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