mV^2/2 = G*Mmars*m/Rmars
V^2 = 2*G*Mmars/Rmars
= 2*g'*Rmars
where G is the universal gravity constant and g' is the acceleration of gravity on Mars. Rmars is the radius of mars.
What speed must a rock have to escape Mars?
V^2 = 2*G*Mmars/Rmars
= 2*g'*Rmars
where G is the universal gravity constant and g' is the acceleration of gravity on Mars. Rmars is the radius of mars.
The escape velocity of Mars can be calculated using the formula:
Ve = sqrt(2 * G * M / R)
Where:
Ve is the escape velocity
G is the gravitational constant (approximately 6.674 × 10^-11 m^3 kg^-1 s^-2)
M is the mass of Mars (approximately 6.39 × 10^23 kg)
R is the radius of Mars (approximately 3.37 × 10^6 m)
Plugging in these values, we can calculate the escape velocity of Mars:
Ve = sqrt(2 * 6.674 × 10^-11 * 6.39 × 10^23 / 3.37 × 10^6)
Calculating this result, we find that the escape velocity of Mars is approximately 5.03 km/s (kilometers per second).
Therefore, for a rock to escape Mars, it would need to have a velocity of at least 5.03 km/s. Any object with a speed greater than this value would be able to overcome the gravitational pull of Mars and travel into space.