Asked by Tia
How many ml of a 2 M solution of HCL would be needed to neutralize 2 ml of a 5 M solution of KOH?
Answers
Answered by
drwls
You have .002 liter x 5 (mole/l) = 0.010 moles of base.
You will need an equal number of moles of acid
X (liters) * 2 mol/liter = 0.01 mole
X = 0.005 l = 5 ml
You will need an equal number of moles of acid
X (liters) * 2 mol/liter = 0.01 mole
X = 0.005 l = 5 ml
There are no AI answers yet. The ability to request AI answers is coming soon!