Asked by Confused
The function f is twice differentiable, and the graph of f has no points of inflection. If f(6)+3, f'(6)=-1/2, and f"(6)=-2, which of th following could be the value of f(7).
A.)2
B.)2.5
C.)2.9
D.)3
E.)4
the answer is A. but what are the steps to reach this answer?
A.)2
B.)2.5
C.)2.9
D.)3
E.)4
the answer is A. but what are the steps to reach this answer?
Answers
Answered by
drwls
Don't you mean f(6) = 3?
A Taylor series, expanded about x = 6, says that
f(7) = f(6) + f'(6)*1 + (1/2!)*f"(x)*1^2 + ...
= 3 -(1/2) -(2/2)
+ (higher order terms)
= 1.5 + higher order terms
With a large positive third derivative, any of the values listed could be possible.
I am also confused
A Taylor series, expanded about x = 6, says that
f(7) = f(6) + f'(6)*1 + (1/2!)*f"(x)*1^2 + ...
= 3 -(1/2) -(2/2)
+ (higher order terms)
= 1.5 + higher order terms
With a large positive third derivative, any of the values listed could be possible.
I am also confused
There are no AI answers yet. The ability to request AI answers is coming soon!