How do I calculate the amount of heat needed to convert 96g of ice at -24 degrees celciua to water at 28 degrees celciua?

Answer 1

the sum of the heats gained is the total heat.
heatgained by ice from -24tozero + heatgained by ice melting+ heat gained by water from 0 to 28= total heat
mass*specificheatice*(0-(-24))+ mass*heatfusion + mass*specificheatwater*(28-0)= total heat