To evaluate g(x) when x=k, we substitute k for x in the expression
g(k)=(k + 1)/k
or
g(k-1) = ( k-1 + 1) / (k-1)
So
1. g(1)=(1+1)/1=2
I'll leave 2 - 4 as exercise for you.
Pour your answers for a check if you wish.
If g(x) = (x + 1)/x,find
a) g(1) b) g(0) c) g(-1) d) g(x - 1)
3 answers
a) g(1) = (1 + 1)/1 = 2/1 = 2
b) g(0) =( 0 + 1)/0 = 1/0 = ¡Þ
c) g(-1) = (-1 + 1)/-1 = 0/-1 = 0
d) g(x-1) = {(x ¨C 1) + 1}/(x ¨C 1) = x/(x ¨C 1)
b) g(0) =( 0 + 1)/0 = 1/0 = ¡Þ
c) g(-1) = (-1 + 1)/-1 = 0/-1 = 0
d) g(x-1) = {(x ¨C 1) + 1}/(x ¨C 1) = x/(x ¨C 1)
(a) is correct.
For (b), you have probably indicated ∞ as the answer, although I prefer to use the term "undefined".
(c) is correct.
For (d), I suppose "¨C" is meant to be a minus sign, in which case it is correct.
For (b), you have probably indicated ∞ as the answer, although I prefer to use the term "undefined".
(c) is correct.
For (d), I suppose "¨C" is meant to be a minus sign, in which case it is correct.
1 answer