remember
INT vdu=uv= INT udv ?
let du= x^-1/3 u= 3/2 x^2/3
v= (4x+3)
so, your above integral must equal
uv-INT udv
or
3/2 x^(2/3)*(4x+3)-INT 6 x^-2/3 dx
and you can finish that.
Could someone answer this question so I understand it. Thanks.
Find the antiderivitive of the following derivitive that satisfies the given condition.
dy/dx = 4x+4/3rd root of x
y(1)=0
y(x)=
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