Asked by Jacob

Sam invested $1950 part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% invest was 6$ more then twice the income from the 6% investment. how much did he invest at each rate
Answered by bobpursley
let S be the amount at six percent, E be the amount at Eight percent.

S+E=1950

.06S=2*.08E+6

can you handle if from here?
Answered by Jacob
Not really having trouble with this one for some reason
Answered by bobpursley
well, s=1950-E
so
.06(1950-E)=2(.08E)+6
now solve for E.
then to get S,subtract E from 1950
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