Asked by Ana
Two wires run parallel to each other with currents I1 = -60.3 A, and I2 = 44.1 A. If they are a = 0.12 m apart, what is the magnitude of the force (N) per meter of length?
I used the formula
(f/L)=Uo(I1)(I2)/(2(pi)(r))
I got 4.43810^-2(N/m)but it was wrong..I'm not sure what mistake is.
I used the formula
(f/L)=Uo(I1)(I2)/(2(pi)(r))
I got 4.43810^-2(N/m)but it was wrong..I'm not sure what mistake is.
Answers
Answered by
drwls
What did you use for Mu-zero? It should be
4 pi x 10^-7 Henrys/meter
The force should be a repulsion, since the currents are in opposite directions.
Your number looks too high.
4 pi x 10^-7 Henrys/meter
The force should be a repulsion, since the currents are in opposite directions.
Your number looks too high.
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