Asked by maria

At a neighboring university, the average salary is also $45,000 and the distribution is normal. If $47,000 has a z score of 1.5, what is the standard deviation?
Answered by MathGuru
Use the z-score formula to solve for standard deviation.

z = (x - mean)/sd

1.5 = (47000 - 45000)/sd

I'll let you take it from here.
Answered by Anonymous
3000