Asked by nena
What are the values of a and b.if any,where a|b-2|<0?
please some sugestions
please some sugestions
Answers
Answered by
Henry
a[b-2]< 0,
A positive number and a negative number of equal magnitude has equal absolute values. Therefore, we must solve 2 Eqs:
Eq1: a(b-2)< 0.
Eq2: a(-b+2) < 0.
a(b-2) < 0,
Divide both sides by a:
b-2 < 0,
b < 2.
A positive number and a negative number of equal magnitude has equal absolute values. Therefore, we must solve 2 Eqs:
Eq1: a(b-2)< 0.
Eq2: a(-b+2) < 0.
a(b-2) < 0,
Divide both sides by a:
b-2 < 0,
b < 2.
Answered by
Henry
a[b-2]< 0,
A positive number and a negative number of equal magnitude has equal absolute values. Therefore, we must solve 2 Eqs:
Eq1: a(b-2)< 0.
Eq2: a(-b+2) < 0.
Eq1: a(b-2) < 0,
Divide both sides by a:
b-2 < 0,
b < 2.
Divide both sides by (b-2):
a < 0.
Solution Set: b < 2, and a < 0.
Eq2: a(-b+2) < 0.
Divide both sides by a:
-b + 2 < 0,
-b < -2,
b > 2.
Divide both sides by (-b+2):
a < 0.
Solution set: b > 2, and a < 0.
A positive number and a negative number of equal magnitude has equal absolute values. Therefore, we must solve 2 Eqs:
Eq1: a(b-2)< 0.
Eq2: a(-b+2) < 0.
Eq1: a(b-2) < 0,
Divide both sides by a:
b-2 < 0,
b < 2.
Divide both sides by (b-2):
a < 0.
Solution Set: b < 2, and a < 0.
Eq2: a(-b+2) < 0.
Divide both sides by a:
-b + 2 < 0,
-b < -2,
b > 2.
Divide both sides by (-b+2):
a < 0.
Solution set: b > 2, and a < 0.
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